MathOverflow
Tyma Gaidash's user avatar
Tyma Gaidash's user avatar
Tyma Gaidash's user avatar
Tyma Gaidash
  • Member for 2 years
  • Last seen more than a week ago
Profile Activity
Stats
125
reputation
0
reached
0
answers
0
questions
Communities
View all
About

Maybe “Tyma” stands for “The Yearning Math Aficionado”. Perhaps “Gaidash” stands for “Great at Inventing Desirable and Smart Hints”.

Together they make up Tyma Gaidash, the yearning math aficionado who is great at inventing desirable and smart hints.

It is just a hobby. I also teach on Gaidash.com

Badges
This user doesn’t have any gold badges yet.
This user doesn’t have any silver badges yet.
2
bronze badges
Posts

This user hasn’t posted yet.

Top network posts
View all network posts
62
Evaluating $\sum\limits_{x=2}^\infty \frac{1}{!x}$ in exact form.
16
Integral over domain of infinite tetration of x over extended domain from 0 to $\sqrt[e]e$. Possible $\int_{e^{-e}}^{e^\frac1e} x^{x^{…}}dx$ solution.
15
Is there an exact solution for $\large\int \frac{dx}{\tan^{-1}(x)}$?
13
Why Dottie$=2\sqrt{I^{-1}_\frac12(\frac 12,\frac 32)-I^{-1}_\frac12(\frac 12,\frac 32)^2} = \sin^{-1}\big(1-2I^{-1}_\frac12(\frac 12,\frac 32)\big)$?
12
Arc Length Integral of $x^x$ from 0 to 1 in closed form.

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.