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I want to answer my old closed question myself.

Is there a formula or algorithm to remove infinitesimal and oscillating parts from an expression while keeping finite and infinite ones?

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    $\begingroup$ Aaron Meyerowitz, who indicated some interest at the time, took a stab at the question but ended up with more questions. The other participant was LSpice, who replied in comments, but mostly he also had more questions. Instead of asking and answering yourself in one shot, which is usually not appreciated if history in any guide, do you see a way of re-asking the question so that the meaning of the question is unambiguous but which doesn't give away its own answer? $\endgroup$
    – Todd Trimble Mod
    May 8 at 1:56
  • $\begingroup$ @ToddTrimble I do not see why I should re-ask a duplicate. Since I have an answer now, it is better for this question to have it than remain closed. $\endgroup$
    – Anixx
    May 8 at 1:58
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    $\begingroup$ I'm trying to work with you here. I'm trying to ask whether you are now in a position to reformulate the question so that its meaning becomes clear to others. But I'm not going to argue about this. There used to be an old thread for reopening old closed questions, here: meta.mathoverflow.net/q/223/2926 $\endgroup$
    – Todd Trimble Mod
    May 8 at 2:09
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    $\begingroup$ Unfortunately, MathOverflow is not a personal blog. If your question was closed due to lack of clarity and low interest, and in this specific case also been twice through the review queue and was left closed, the fact that you have an answer is irrelevant to the situation. This would be a good use of a personal blog about mathematics where you can post your question and your answer. $\endgroup$
    – Asaf Karagila Mod
    May 8 at 9:05
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    $\begingroup$ I concur with Asaf that you finding an answer to your own question is probably more valuable to you, and that eventually this material being public in its own channel (a blog, a preprint, whatever) is probably best. $\endgroup$
    – David Roberts Mod
    May 10 at 4:33

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