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Mar 17, 2017 at 10:13 history edited CommunityBot
replaced http://meta.mathoverflow.net/ with https://meta.mathoverflow.net/
Nov 16, 2014 at 12:42 comment added Yemon Choi in interests of fairness, vote this comment up if you disagree with the view in my previous comment
Nov 16, 2014 at 12:41 comment added Yemon Choi To illustrate my previous remark: my view is that mathoverflow.net/questions/187303/… is a much better question than mathoverflow.net/questions/187246/…
Nov 14, 2014 at 14:30 comment added Todd Trimble Mod Some highly upvoted questions asked by some of our most illustrious users are more or less asked out of simple curiosity. You are in good company here.
Nov 14, 2014 at 14:07 comment added Yemon Choi @LSpice It depends if it's inane, or thoughtful :)
Nov 14, 2014 at 13:51 vote accept LSpice
Nov 14, 2014 at 13:50 comment added LSpice @YemonChoi, then perhaps you will enjoy my upcoming question about the cohomology of sheaves of von Neumann algebras? :-)
Nov 14, 2014 at 13:30 history edited user9072
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Nov 14, 2014 at 13:21 comment added Yemon Choi Further to @JonBeardsley's comment: I always am troubled by using "level" as an indicator, since it is possible to ask very fruitful or thoughtful questions that only require definitions one would see as an undergraduate, and possible to ask very inane questions about sheaves, von Neumann algebras, cohomology, whatever
Nov 14, 2014 at 11:14 answer added Brendan McKay timeline score: 16
Nov 10, 2014 at 4:25 comment added Jonathan Beardsley I think people should in general be less worried about asking questions that aren't at high enough of a level. If you're considering that issue, you're not the sort of person that rule is meant to exclude (it seems). Moreover, it's not the end of a world to have a question closed or transferred. If it happened because it's too easy, that's kind of an answer in itself. So just ask!
Nov 7, 2014 at 2:52 comment added LSpice @JoelDavidHamkins, thanks for the encouragement! It is at mathoverflow.net/q/186439/2383.
Nov 7, 2014 at 2:43 comment added Joel David Hamkins My initial reaction is: great question; please ask it! I'd love to see an answer.
Nov 7, 2014 at 0:49 history edited LSpice CC BY-SA 3.0
Edited to clarify question
Nov 6, 2014 at 23:54 answer added Stefan KohlMod timeline score: 7
Nov 6, 2014 at 23:53 comment added The Masked Avenger You might search MathOverflow for questions involving vector spaces and the axiom of choice. You may find something to help answer the proposed question. With choice, I think the answer is yes because the subset of Perm X "has enough torsion", but I do not know a convincing proof.
Nov 6, 2014 at 22:19 history asked LSpice CC BY-SA 3.0